Comments on: Knewton Challenge Discussion – GMAT Problem Solving (Cello-Viola Pairs)
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/
Tue, 14 Apr 2015 19:37:41 +0000hourly1http://wordpress.org/?v=4.2.3By: gandalf the great
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-6231
Wed, 23 Oct 2013 00:35:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-6231TROLL TROLL TROLL TROLL
]]>By: Jose Luis Ponce
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-6141
Wed, 25 Sep 2013 15:19:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-6141The answer is A. Probability is (Number of pairs) / (Total combinations from 2 sets) = 90 / (800 x 600) = 3/16000. Good question,
]]>By: Victory Lap Hero
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-6118
Thu, 19 Sep 2013 00:02:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-6118Answer A because: 600 Cello 90 of same tree so the probability of picking one of those is 0.15, next you pick one violin out of 800 the odds being 1/800, multiply those two probabilities together to get a really small fraction, then calculate the division of the answers and realize A yeilds the same small fraction. To check I tried doing the math in reverse choosing first a Violin then a cello
]]>By: gyamfi frederick
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-5588
Wed, 17 Jul 2013 12:16:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-5588the correct answer is 1/90. since we have only 90 pairs made from one tree, it implies there are 90 trees hence the probability that two instruments are made from one tree is 1/90…
]]>By: K
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-5527
Tue, 25 Jun 2013 17:48:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-552790/(600*800) is the easiest and quickest way.
My rationale when first reading through was:
You have a 90/800 chance of picking a cello made from a paired tree. Multiply by the 1/600 chance that you pick the corresponding viola. The math is the same, but arrived using more ‘step by step’ logic.
]]>By: Favour Elekwachi
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-4304
Tue, 07 Aug 2012 09:30:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-4304the answer is a
]]>By: Favour Elekwachi
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-4303
Tue, 07 Aug 2012 09:20:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-4303the answer is c
]]>By: Guest
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-3753
Thu, 01 Mar 2012 03:56:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-3753It’s A
]]>By: EvaJager
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-1642
Mon, 09 May 2011 22:19:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-1642Use the basic definition of probability – number of desired outcomes over the total number of outcomes.
Desired outcomes – 90 (there are exactly 90 pairs of cello & viola, each from the same one tree).
Total number of cello & viola pairs – 800×600.
Therefore, the probability is 90/800×600=3/16000 (after reducing by a factor of 3).
The same simple way as TNO suggested.
]]>By: EvaJager
http://www.knewton.com/blog/test-prep/knewton-challenge-discussion-gmat-problem-solving-cello-viola-pairs/#comment-2480
Mon, 09 May 2011 22:19:00 +0000http://www.knewton.com/stage/blog/?p=9088#comment-2480Use the basic definition of probability – number of desired outcomes over the total number of outcomes.
Desired outcomes – 90 (there are exactly 90 pairs of cello & viola, each from the same one tree).
Total number of cello & viola pairs – 800×600.
Therefore, the probability is 90/800×600=3/16000 (after reducing by a factor of 3).
The same simple way as TNO suggested.
]]>